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Q: Is 367 dividable by 3

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Any number dividable by six must also be dividable by 3 as well as by 2. Nice Question!

3/42 = 1/14

No as it is dividable by 3 (123/3=41)

0.75.... Think of it as 3/4 which is .75

No - 367/3 = 122.3 recurring (that is, 122.3333...)

yes 7 is dividable by 5670 the answer is 810

there is no answer because numbers go on forever!

1, 3, 7, 21, 49, 147.

1080

1, 2, 3, 6, 29, 58, 87, 174.

comes after 3 and before five. it is dividable by 2.

Not evenly; 23,456,789 divided by three is 7,818,929.67

heres an example 12,342 is because 1+2+3+4+2=12 3 can go into 12

122.3333

Yes. If you add 1, 2, and 9 together, it equals 12 and 12 is dividable by 3.

1, 3, 7, 9, 21, 49, 63, 147, 441

Dividable

NO

No

No, it is not.

That's "divisible". 3 x 66 = 198 so 66 is your answer.

Not evenly; 367 / 3 is equal to 122.33

I'm not quite sure about that theory, but if all the numbers in the number add up to a number that's dividable by 3, then the number itself would then be divisible by 3. Ex. 141 1+4+1= 6 6 is divisible by 3, so 141 is too. 141/3= 47.

2 is the only prime number dividable by 2. to be a prime number, it must only be dividable by 1 and itself. This is the reason why 2 is the only prime number dividable by 2. If any other number was dividable by two then it would not be prime any more

367 = 367/1000